Question
Question: The first term of an arithmetic sequence is equal to 200 and the common difference is equal to -10. ...
The first term of an arithmetic sequence is equal to 200 and the common difference is equal to -10. Find the value of the 20th term.
Solution
We will use the formula to determine the nth term of an arithmetic progression (A. P.) given by: an=a+(n−1)d , where a is the first term of the A. P. and d is the common difference. Upon substituting the values of a, n and d, we will get the value of 20th term.
Complete step-by-step answer:
We are given the first term, of an arithmetic sequence as 200.
Its common difference, d is -10.
We need to calculate the value of the 20th term.
We know that the formula to calculate the nth term of an A. P. is given as: an=a+(n−1)d, where a is the first term of the sequence and d is the common difference of the A. P.
Here, n = 20, a = 200 and d = –10. Substituting these values in the equation an=a+(n−1)d, we get
⇒an=a+(n−1)d ⇒a20=200+(20−1)(−10) ⇒a20=200−10(19) ⇒a20=200−190 ⇒a20=10
Therefore, the value of the 20th term of the arithmetic sequence whose first term is 200 and common difference is –10 is calculated to be 10.
Note: In this question, we have only used the formula of nth term by simply putting the values given in the question. It is a straightforward question based on direct formula. You may go wrong only in the determination of the value of the 20th term (in terms of the calculation part).
In mathematics, an arithmetic progression is a sequence of numbers such that the difference between two consecutive terms is always a constant (termed as common difference). For example, 2, 4, 6, 8, 10, 12, … is an arithmetic progression with a common difference of 2.