Question
Question: The first term of an arithmetic sequence is equal to 200 and the common difference is equal to \[ - ...
The first term of an arithmetic sequence is equal to 200 and the common difference is equal to −10. Find the value of the 20th term.
Solution
Here, we will find the common difference and then use the formula of nth term of the arithmetic progression A.P., that is, an=a+(n−1)d, where a is the first term and d is the common difference. Apply this formula, and then substitute the value of a,d and n in the obtained equation to find the value of the required term.
Complete step by step answer:
We are given that the first term of an arithmetic sequence is 200 and the common difference is −10.
We know that the arithmetic progression is a sequence of numbers in order in which the difference of any two consecutive numbers is a constant value.
We will now find the value of first term a and the common differenced, we get
a=200
d=−10
We will use the formula of nth term of the arithmetic progression A.P., that is, an=a+(n−1)d, where a is the first term and d is the common difference.
We know that n=20.
Substituting these values of n, a and d in the above formula for the sum of the arithmetic progression, we get
Thus, the 20th term of the given AP is 10.
Note: In solving these types of questions, you should be familiar with the formula of sum of the arithmetic progression and their sums. Some students use the formula to find the sum, S=2n(a+l), where l is the last term, but we do not have the to find the value of an so it will be wrong. We can also find the value of nth term by find the value of Sn−Sn−1, where Sn=2n(2a+(n−1)d), where a is the first term and d is the common difference. But this is a longer method, which takes time, so we will use the above method. One should know the an is the nth term in the geometric progression.