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Question

Physics Question on Electromagnetic waves

The first overtone of a stretched wire of given length is 320Hz320 \,Hz. The first harmonic is :

A

320 Hz

B

160 Hz

C

480 Hz

D

640 Hz

Answer

160 Hz

Explanation

Solution

If a wire, vibrates in p segments, then its frequency is given by
n=p2lTmn=\frac{p}{2 l} \sqrt{\frac{T}{m}}
The frequency of first harmonic is
n=12lTm...(i)n=\frac{1}{2 l} \sqrt{\frac{T}{m}}\,\,\, ...(i)
The frequency of second harmonic or first overtone is
n=22lTm...(ii)n'=\frac{2}{2 l} \sqrt{\frac{T}{m}}\,\,\, ...(ii)
n=2nn'=2 n
n=n2=3202=160Hzn=\frac{n'}{2}=\frac{320}{2}=160 \,Hz