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Question: The first order rate constant for the decomposition of \(N_{2}O_{5}\)is \(6.2 \times 10^{- 4}\sec^{-...

The first order rate constant for the decomposition of N2O5N_{2}O_{5}is 6.2×10−4sec⁡−16.2 \times 10^{- 4}\sec^{- 1}{}. The half-life period for this decomposition in seconds is

A

1117.7

B

111.7

C

223.4

D

160.9

Answer

1117.7

Explanation

Solution

t1/2=0.693k=0.6936.2×10−4=1117.7sec⁡\mathbf{t}_{\mathbf{1/2}}\mathbf{=}\frac{\mathbf{0.693}}{\mathbf{k}}\mathbf{=}\frac{\mathbf{0.693}}{\mathbf{6.2}\mathbf{\times}\mathbf{1}\mathbf{0}^{\mathbf{-}\mathbf{4}}}\mathbf{= 1117.7}\mathbf{\sec}