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Question

Engineering Mathematics Question on Taylor series

The first non-zero term in the Taylor series expansion of (1x)ex(1-x)-e^{-x} about x=0x = 0 is

A

1

B

-1

C

x22\frac{x^2}{2}

D

x22-\frac{x^2}{2}

Answer

x22-\frac{x^2}{2}

Explanation

Solution

The correct option is (D) :x22-\frac{x^2}{2}