Question

The first member of the Balmer’s series of the hydrogen has a wavelength l. The wavelength of second member is –

• A. $\frac{27\lambda}{20}$
• B. $\frac{20\lambda}{27}$
• C. $\frac{27}{20\lambda}$
• D. None

Answer 1

Answer: (B)

$\frac{20\lambda}{27}$

Answer 2

$\frac{1}{\lambda}$ = RZ²$\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right)$