Question
Question: The first excited state of hydrogen atom is higher to its ground energy level by\[10.2eV\]. The temp...
The first excited state of hydrogen atom is higher to its ground energy level by10.2eV. The temperature necessary to excite hydrogen atom to first excited state will be
A)0.88KB)7.88×102KC)7.88×103KD)7.88×104K
Solution
We will use the relation between kinetic energy and temperature to solve this problem. We must know that, according to the law of equipartition of energy, energy will be distributed on each degree of freedom except vibrational mode as 21kT. Here, k is the Boltzmann constant. So, we will find the temperature necessary to get an energy of 10.2eV. We must know that hydrogen is a monatomic gas.
Complete step by step answer:
Firstly we will try to understand what the law of equipartition of energy is. According to this law, in a thermal equilibrium, the total energy of a gas is distributed among all energy modes. That is the degree of freedom.
We know, hydrogen is a monatomic gas. So, monoatomic gases have a degree of freedom of 3. There are no vibrational modes for a monatomic gas. So, the energy of this hydrogen gas will be represented as,
K.E=23kT
Now, the energy of the first state is given as 10.2eV. We will convert it into joules by multiplying with1.6×10−19.
⇒E=10.2×1.6×10−19=1.632×10−18
Now, we will find the temperature required for attaining this energy.