Question
Question: The first excitation potential of a given atom is 10.2 V then the ionisation potential is: \(\begi...
The first excitation potential of a given atom is 10.2 V then the ionisation potential is:
A. 10.2VB. 13.6VC. 30.6VD. 20.4V
Explanation
Solution
First we will find quantum number (n) and by using quantum number we will find total energy on first state by using the formula n2E after that we will take difference between first and second state so that we can find ionisation potential (E)
Formula used:
(T.E)F=−n2E
Where, E = ionisation potential
n = quantum number
Complete answer:
Given that
First excitation potential is 10.2V
Now the quantum number on first state is n = 2
Now the total energy in ground state is
(T.E)g=−E
Total energy in first state is
(T.E)F=−n2E
Now,
∴The potential of given atom = (T)F−(T.E)g