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Question

Physics Question on Wave optics

The first diffraction minimum due to single slit diffraction is θ,\theta , for a light of wave length 5000? 5000\, ? . If the width of the slit is 1×104cm,1\times {{10}^{-4}}cm, then the value of θ\theta is:

A

3030{}^\circ

B

4545{}^\circ

C

6060{}^\circ

D

1515{}^\circ

Answer

3030{}^\circ

Explanation

Solution

The distance of first diffraction minimum from the central principal maximum. x=Dλdx =\frac{D \lambda}{d} xD=λd\frac{x}{D} =\frac{\lambda}{d} or d=λsinθd =\frac{\lambda}{\sin \theta} sinθ=λd=5000×1081×104\Rightarrow \sin \theta =\frac{\lambda}{d}=\frac{5000 \times 10^{-8}}{1 \times 10^{-4}} sinθ=0.5=sin30\sin \theta =0.5=\sin 30 θ=30\theta =30^{\circ}