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Question: The first and last term of an A.P. are a and*l* respectively. If s be the sum of all terms of the A....

The first and last term of an A.P. are a andl respectively. If s be the sum of all terms of the A.P., then the common difference is –

A

l2a22s(l+a)\frac{l^{2} - a^{2}}{2s - (l + a)}

B

l2a22s(la)\frac{l^{2} - a^{2}}{2s - (l - a)} f

C

l2+a22s+(l+a)\frac{l^{2} + a^{2}}{2s + (l + a)}

D

l2+a22s(l+a)\frac{l^{2} + a^{2}}{2s - (l + a)}

Answer

l2a22s(l+a)\frac{l^{2} - a^{2}}{2s - (l + a)}

Explanation

Solution

l = a + (n – 1) d ̃ n = la+dd\frac{l - a + d}{d}

Now S = n2\frac{n}{2} (a + l)

̃ S = la+d2d\frac{l - a + d}{2d} (a + l)

d =l2a22s(a+1)\frac{l^{2} - a^{2}}{2s - (a + 1)}.