Question
Question: The first and last term of an AP are 8 and 65 respectively. If the sum of all its terms in 730, find...
The first and last term of an AP are 8 and 65 respectively. If the sum of all its terms in 730, find its common difference.
Solution
The product of the members of a finite arithmetic progression with an initial element a1, common differences d, and n elements in total is determined in a closed expression
This is a generalization from the fact that the product of the progression 1×2×⋯×n is given by the factorial n ! and
that the product m×(m+1)×(m+2)×⋯×(n−2)×(n−1)×n for positive integers m and n is given by(m−1)!n!
Complete step-by-step answer:
In mathematics, an arithmetic progression (AP) or arithmetic sequence is a sequence
of numbers such that the difference between the consecutive terms is constant. For instance,
the sequence 5,7,9,11,13, 15,…is an arithmetic progression with a common difference of 2 .
If the initial term of an arithmetic progression is a1 and the common difference of successive
members are d, then the nth term of the sequence (an) is given by:
an=a1+(n−1)d and in general,an=am+(n−m)d.
Given 730=2n(a+l)
l=65
a=8
⇒ 730=2n(8+65)
⇒ 730=2n(73)
⇒ 10=2n
20=n
Now 65=l=a+(n−1)d
⇒ 65=8+(20−1)d
⇒ 65−8=19d
⇒ 57=19d
⇒ d=1957=3
The common difference is 3.
Note: A finite portion of an arithmetic progression is called a finite arithmetic progression and sometimes just called an arithmetic progression. The sum of a finite arithmetic progression is called an arithmetic series. The standard deviation of any arithmetic progression can be
calculated as σ=∣d∣12(n−1)(n+1)
where n is the number of terms in the progression and d is the common difference between terms. The formula is very similar to the standard deviation of a discrete uniform distribution.