Question

The figure shows (x, t), (y, t) diagram of a particle moving in 2-dimensions. If the particle has a mass of 500 g, the force acting on the particle is :

• A. 1 N along y-axis
• B. 1 N along x-axis
• C. 0.5 N along x-axis
• D. 0.5 N along y-axis

Answer 1

Answer: (A)

1 N along y-axis

Answer 2

Since the graph between x and t is a straight line and passing through the origin

$\therefore x = t$

Since the graph between y and t is a parabola

$\therefore y = t^{2}$

$\therefore v_{x} = \frac{dx}{dt} = 1anda_{x} = \frac{dv_{x}}{dt} = 0$

And $v_{y} = \frac{dy}{dt} = 2tanda_{y} = 2ms^{- 2}$

The force acting on the particle is

$F = ma_{y} = (0.5kg)(2ms^{- 2}) = 1N$along y-axis