Question

The figure shows the velocity $(v)$ of a particle plotted against time $(t)$. Choose correct options.

• A. The particle changes its direction of motion at some point
• B. The acceleration of the particle remains constant
• C. The displacement of the particle is zero
• D. The initial and final speeds of the particle are the same

Answer 1

Answer: (A), (B), (C), (D)

A, B, C, D

Answer 2

The given graph is a velocity-time graph.

1. Direction change (A): Velocity changes from negative to positive, passing through zero at $t=T$, indicating a change in direction.

2. Constant acceleration (B): The graph is a straight line, meaning its slope (acceleration) is constant.

3. Zero displacement (C): The area under the graph from $t=0$ to $t=T$ is negative and equal in magnitude to the area from $t=T$ to $t=2T$, which is positive. The net displacement (total area) is zero.

4. Same initial and final speeds (D): Due to the symmetry of the straight line graph around $t=T$, the magnitude of the initial velocity at $t=0$ is equal to the magnitude of the final velocity at $t=2T$. Hence, initial and final speeds are the same.