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Question: The figure shows the variation of photo current with anode potential for a photo-sensitive surface f...

The figure shows the variation of photo current with anode potential for a photo-sensitive surface for three different radiations. Let and IcI _ { c } be the intensities and va,vbv _ { a } , v _ { b } and be the frequencies of the curves a, b and c respectively.

A

va=vb\mathrm { v } _ { \mathrm { a } } = \mathrm { v } _ { \mathrm { b } } and

B

va=vb\mathrm { v } _ { \mathrm { a } } = \mathrm { v } _ { \mathrm { b } } and IaIcI _ { a } \neq I _ { c }

C

va=vb\mathrm { v } _ { \mathrm { a } } = \mathrm { v } _ { \mathrm { b } } and

D

and

Answer

va=vb\mathrm { v } _ { \mathrm { a } } = \mathrm { v } _ { \mathrm { b } } and

Explanation

Solution

: From the graph, we note that the saturation current is same for curves b and c but different for curve a. therefore intensities of b and c will be equal but different from that of a i.e. IaIbI _ { a } \neq I _ { b } but Ib=IcI _ { b } = I _ { c }As stopping potential is same for curves a and b hence va=vbv _ { a } = v _ { b } thus answer (1) is correct