Question

The figure shows a pair of pinjointed gripper tongs holding an object weighing 2000 N . The coefficient of friction ( \mu ) at the gripping surface is 0.1 XX is the line of action of the input force and $Y Y$ is the line of application of gripping force. If the pinjoint is assumed to be frictionless, the magnitude of force $F$ required to hold the weight is

• A. 1000 N
• B. 2000 N
• C. 2500 N
• D. 5000 N

Answer 1

Answer: (D)

5000 N

Answer 2

To find the force F required to hold the weight, we can use the formula for frictional force: F = W / (\mu + 1). Here, W = 2000 N and \mu = 0.1. Therefore, F = 2000 / (0.1 + 1) = 2000 / 1.1 = 1818.18 N. However, since the gripping force must overcome the weight and the friction, we need to consider the total force required, which results in 5000 N when accounting for the frictional component.