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Question: The Fibonacci sequence is defined by \( a_1 \) = 1 = \( a_2 \) , \( a_n = a_{n-1} + a_{n-2} \) for n...

The Fibonacci sequence is defined by a1a_1 = 1 = a2a_2 , an=an1+an2a_n = a_{n-1} + a_{n-2} for n >2 .
Find an+1/ana_{n+1} / a_n for n = 1,2,3,4,5.

Explanation

Solution

We need to find n=1,2,3,4,5n=1, 2, 3,4,5 separately as the question says. Fibonacci sequence is the series of numbers in which a number is the addition of the last two numbers starting with 00 or 11 . Fibonacci sequence is significant and used to create technical indicators.

Complete answer:
Given a1= 1a{_1}= \ 1
a2= 1a{_2}= \ 1
We need to find a3a{_3} , a4a{_4} , a5a{_5} and a6a{_6}
Given,
an = an1+ an2a{_n}\ = \ a{_{n-1}}+ \ a{_{n-2}} for  n>2\ n > 2
Now we need to find for n=3,n = 3,
a3= a31+ a32= a2+ a1a{_3} = \ a{_{3-1}} + \ a{_{3-2}} = \ a{_2}+ \ a{_1}
=  1+1\ 1 + 1
By adding ,
=  2\ 2
Then need to find for n= 4n = \ 4 ,
a4= a41+ a42= a3+ a2a{_4}= \ a{_{4-1}}+ \ a{_{4-2}} =\ a{_3}+ \ a{_2}
=   2 + 1\ \ 2\ + \ 1
By adding,
=  3\ 3
Next for n =5,n\ = 5,
a5= a51+ a52=a4+ a3a{_5}= \ a{_{5-1}}+ \ a{_{5-2}} = a{_4}+ \ a{_3}
=  3+2\ 3 + 2
By adding,
We get,
=  5\ 5
Finally need to find for  n =6\ n\ = 6
a6= a61+ a62= a5+ a4a{_6} = \ a{_{6-1}}+ \ a{_{6-2}} =\ a{_5}+ \ a{_4}
= 5+35 + 3
By adding,
We get,
= 88
Also given,
an= an1+an2a{_n}= \ a{_{n- 1}}+ a{_{n-2}}
Now here we need to find for n= 1,n = \ 1,
( an+1 /an)= (a1+1 /a1)= ( a2/a1)(\ a{_{n+1}}\ /a{_n})= \ (a{_{1+1}}\ /a{_1} ) =\ (\ a{_2}/a{_1})
By substituting the values,
We get,
= 11\dfrac{1}{1}
=  1\ 1
Then for n=2n = 2
(an+1/an)= (a2+1/ a2)(a{_{n+1}}/a{_n})= \ ( a{_{2+1}}/\ a{_2})
= (a3/ a2)=\ (a{_3}/\ a{_2})
By substituting the values,
We get,
= 21\dfrac{2}{1}
=  2\ 2
Now for n=3n = 3
(an+1/ an)(a{_{n+1}} /\ a{_n}) = ( a3+1/a3)= \ (\ a{_{3+1}}/a{_3} )
= (a4/ a3)= \ (a{_4}/\ a{_3})
By substituting the values,
We get,
= 32\dfrac{3}{2}
Then need to find for n=4n = 4
(an+1/ an)(a{_{n+1}}/\ a{_n}) = (a4+1/= \ (a{_{4+1}}/ a4)=(a5/a4)a{_4})= (a{_5}/a{_4})
By substituting the values,
We get,
= 53\dfrac{5}{3}
Finally for n=5n = 5
(an+1/ an)(a{_{n+1}}/\ a{_n})
= ( a5+1/ a5)(\ a{_{5+1}}/\ a{_5})
=  (a6/ a5)\ (a{_6}/\ a{_5})
By substituting the values,
We get,
= 85\dfrac{8}{5}
Hence the value of (an+1/ an)(a{_{n+1}}/\ a{_n}) when n\ = \ 1,2,3,4,5\ are 1,2,32,53,851,2,\dfrac{3}{2},\dfrac{5}{3},\dfrac{8}{5} respectively.
Final answer :
The value of (an+1/ an)(a{_{n+1}}/\ a{_n}) when n\ = \ 1,2,3,4,5\ are 1,2,32,53,851,2,\dfrac{3}{2},\dfrac{5}{3},\dfrac{8}{5} respectively.

Note:
Another example of Fibonacci sequence is 0,1,1,2,3,5,8,13,21,....0,1,1,2,3,5,8,13,21,.... The expression of the Fibonacci sequence is Xn=Xn1+Xn2X{_n} = X{_{n-1}} + X{_{n-2}} . Mathematically Fibonacci number is strongly related to golden ratio and also closely related to lucas numbers.