Question
Question: The family of straight lines 3(a + 1) x – 4 (a – 1) y+ 3 (a + 1) = 0 for different values of ‘a’ pas...
The family of straight lines 3(a + 1) x – 4 (a – 1) y+ 3 (a + 1) = 0 for different values of ‘a’ passes through a fixed point whose coordinates are
A
(1, 0)
B
(– 1, 0)
C
(–1, –1)
D
None of these
Answer
(– 1, 0)
Explanation
Solution
Given family of lines can be written as
a(3x – 4y + 3) + 3x + 4y + 3 = 0, solve
3x + 4y + 3 = 0 & 3x – 4y + 3 = 0 Ž x = – 1, y = 0