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Question: The extremities of the diagonal of a parallelogram are the points (3,– 4) and (–6, 5). Third vertex ...

The extremities of the diagonal of a parallelogram are the points (3,– 4) and (–6, 5). Third vertex is the point (– 2, 1), then the fourth vertex is-

A

(1, 1)

B

(1, 0)

C

(0, 1)

D

(– 1, 0)

Answer

(– 1, 0)

Explanation

Solution

Mid point of BD = midpoint of AC

h−22\frac{h - 2}{2}= −32\frac{- 3}{2}, k+12\frac{k + 1}{2}= 12\frac{1}{2}

h = –1, k = 0