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Question: The extremities of the base of an isosceles triangle ABC are the points A(2, 0) and B(0, 1). If the ...

The extremities of the base of an isosceles triangle ABC are the points A(2, 0) and B(0, 1). If the equation of the side AC is x = 2, then the slope of the side BC is-

A

43\frac{4}{3}

B

34\frac{3}{4}

C

32\frac{3}{2}

D

3\sqrt{3}

Answer

34\frac{3}{4}

Explanation

Solution

Use AC = BC Ž k = 5/2