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Question

Question: The extension of a wire by the application of load is 3 mm. The extension in a wire of the same mate...

The extension of a wire by the application of load is 3 mm. The extension in a wire of the same material and length but half the radius by the same load is

A

12 mm

B

0.75 mm

C

15 mm

D

6 mm

Answer

12 mm

Explanation

Solution

l=FLAYl1r2l = \frac { F L } { A Y } \Rightarrow l \propto \frac { 1 } { r ^ { 2 } } (F,L and Y are constant)

l2l1=(r1r2)2=(2)2l2=4l1=4×3=12 mm\frac { l _ { 2 } } { l _ { 1 } } = \left( \frac { r _ { 1 } } { r _ { 2 } } \right) ^ { 2 } = ( 2 ) ^ { 2 } \Rightarrow l _ { 2 } = 4 l _ { 1 } = 4 \times 3 = 12 \mathrm {~mm}