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Question

Physics Question on Hooke's Law

The extension in a string obeying Hooke's law vv is xx. The speed of sound in the stretched string is vv. If the extension in the string is increased to 1.5x1.5\, x, the speed of sound will be

A

1.22 v

B

0.61 v

C

1.50 v

D

0.75 v

Answer

1.22 v

Explanation

Solution

Speed of sound V=TμV =\sqrt{\frac{ T }{\mu}}
Also VTV \propto \sqrt{ T }
So TxT \propto x
V2V1=1.5xx\frac{ V _{2}}{ V _{1}}=\sqrt{\frac{1.5 x }{ x }}
V2=1.5V=1.22VV _{2}=\sqrt{1.5} \,V =1.22\, V