Question
Question: The expression \(\Rightarrow\) \(\sin 4\theta(2\cos 3\theta - 1) = 0 \Rightarrow \sin 4\theta = 0,\ ...
The expression ⇒ sin4θ(2cos3θ−1)=0⇒sin4θ=0, cos3θ=21 has the positive values for x, given by.
A
4θ=0
B
⇒
C
For all 4θ=π
D
⇒
Answer
For all 4θ=π
Explanation
Solution
The expression is
⇒
= 2cos2θ−3cosθ−3=0
Obviously, ⇒. Hence it is positive for all value of x.