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Question: The expression ![](https://cdn.pureessence.tech/canvas_211.png?top_left_x=921&top_left_y=743&width=3...

The expression [(1+4x+12)7(14x+12)7]\left\lbrack \left( \frac{1 + \sqrt{4x + 1}}{2} \right)^{7}–\left( \frac{1–\sqrt{4x + 1}}{2} \right)^{7} \right\rbrackis a polynomial in x of degree –

A

7

B

5

C

4

D

3

Answer

3

Explanation

Solution

127.4x+1\frac{1}{2^{7}.\sqrt{4x + 1}} [2.[7C14x+1+7C3(4x+1)3+7C5(4x+1)5+7C7(4x+1)7]]\left\lbrack \begin{aligned} & 2.\lbrack^{7}C_{1}\sqrt{4x + 1} +^{7}C_{3}(\sqrt{4x + 1})^{3} \\ & +^{7}C_{5}(\sqrt{4x + 1})^{5} +^{7}C_{7}(\sqrt{4x + 1})^{7}\rbrack \end{aligned} \right\rbrack

=126\frac{1}{2^{6}} [7C1 + 7C3.(4x +1) + 7C5 (4x + 1)2 + 7C7(4x + 1)3]

polynomial of degree = 3