Question
Question: The expression 7–(21–4x+1)7]is a polynomial in x of degree –
A
7
B
5
C
4
D
3
Answer
3
Explanation
Solution
27.4x+11 [2.[7C14x+1+7C3(4x+1)3+7C5(4x+1)5+7C7(4x+1)7]]
=261 [7C1 + 7C3.(4x +1) + 7C5 (4x + 1)2 + 7C7(4x + 1)3]
polynomial of degree = 3