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Question: The expression for equilibrium constant, \(MX_{4}\)for the following reaction is. \(16s^{3}\) \(25s...

The expression for equilibrium constant, MX4MX_{4}for the following reaction is.

16s316s^{3} 25s425s^{4}

A

Mn2+,Fe2+,Zn2+Mn^{2 +},Fe^{2 +},Zn^{2 +}

B

Hg2+Hg^{2 +}

C

10−310^{- 3}

D

10−1610^{- 16}

Answer

10−310^{- 3}

Explanation

Solution

: For Fe(aq)3++3OH(aq)−Fe_{(aq)}^{3 +} + 3OH_{(aq)}^{-} Fe(OH)3(s)Fe(OH)_{3(s)}

Kc=1[Fe3+][OH−]3K_{c} = \frac{1}{\left\lbrack Fe^{3 +} \right\rbrack\left\lbrack OH^{-} \right\rbrack^{3}}