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Question

Chemistry Question on d block elements

The expression for effective magnetic moment (μeff)(\mu _{\text{eff}}) is

A

μeff=n(n+2)BM\mu_{\text{eff}}=\sqrt{n(n+2)}\,BM

B

μeff=2(n+2)BM\mu_{\text{eff}}=\sqrt{2(n+2)}\,BM

C

μeff=n(2n+2)BM\mu_{\text{eff}}=\sqrt{n(2n+2)}\,BM

D

μeff=n(n+1)BM\mu_{\text{eff}}=\sqrt{n(n+1)}\,BM

Answer

μeff=n(n+2)BM\mu_{\text{eff}}=\sqrt{n(n+2)}\,BM

Explanation

Solution

Effective magnetic moment (μeff)(\mu_{\text{eff}}) is
μ=n(n+2)\mu =\sqrt{n(n+2)}
where, n=n = number of unpaired electrons.
A single unpaired electron has a magnetic moment of 1.731.73 Bohr magneton (BM)(BM).