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Question

Question: The expansion of unit mass of a perfect gas at constant pressure is shown in the diagram. Here <img...

The expansion of unit mass of a perfect gas at constant pressure is shown in the diagram. Here

A

a = volume, b = 0C temperature

B

a = volume, b = K temperature

C

a = 0C temperature, b = volume

D

a = K temperature, b = volume

Answer

a = 0C temperature, b = volume

Explanation

Solution

In the given graph line have a positive slop with X-axis and negative intercept on Y-axis.

So we can write the equation of line y = mxc ...... (i)

According to Charle’s law Vt=V0273t+V0V_{t} = \frac{V_{0}}{273}t + V_{0}, by rewriting this equation we get

t=(273V0)Vt273t = \left( \frac{273}{V_{0}} \right)V_{t} - 273 ......(ii)

By comparing (i) and (ii) we can say that time is represented on Y-axis and volume in X-axis.