Question
Question: The exhaust velocity of gases with respect to a small rocket of mass 25 kg is \(28\times 10^2 m/s\)....
The exhaust velocity of gases with respect to a small rocket of mass 25 kg is 28×102m/s. At what rate the fuel must burn so that it may rise up with an acceleration of 9.8m/s2 ?
A. 175 kg/s
B. 1.75 kg/s
C. 0.175 kg/s
D. Zero
Solution
A rocket is an aircraft/ spacecraft or a vehicle which is basically used to launch anything from the earth to space. The material to be launched is known as ‘payload’. We can explore different parts of the universe using rockets.
Formula used: FT=vrdtdm
Complete step by step answer:
The launch of a rocket is based on Newton’s laws of motion. The main fact behind it is that the fuel is ejected from the bottom part of the rocket at a very high rate so that the rocket experiences an upward thrust (due to momentum of fuel) and this thrust when gets greater than the weight of the rocket, the rocket gets launched.
The thrust force which the fuel exerts on the rocket is given by FT=vrdtdm, where vr is the velocity of fuel with respect to rocket and dtdm is the rate of burn of fuel.
Given vr=28×102m/s=2800m/s
Now, force that it has to experience = Fnet=m×a=25×9.8=245N
But, gravity will also play its role here, hence;
FT−mg=Fnet
FT=Fnet+mg
FT=245+25×9.8=245+245=490N
Now, putting the values in the equation: FT=vrdtdm, we get;
490=dtdm×2800
⟹dtdm=0.175kg/s
So, the correct answer is “Option C”.
Note: The phenomenon of rocket launching is based on Newton’s third law which states that “Every action has an equal and opposite reaction. The fuel is ejected with respect to the rocket continuously at a very high speed and hence the fuel in turn applies force upwards on the rocket, which lifts it. Hence in this way, the rocket gets launched. Chance of mistake is that students might think that the rocket being heavy, its weight could be neglected. But it is not so. Unless specified, we have to always consider the effect of gravity.