Question

The excess pressure of one soap bubble is four times more than that in the other. Then the ratio of volumes of the first bubble to the second, is

• A. 1 : 64
• B. 1 : 4
• C. 64 : 1
• D. 1 : 2

Answer 1

Answer: (A)

1 : 64

Answer 2

$\frac { \mathrm { P } _ { 1 } } { \mathrm { P } _ { 2 } } = 4$ or P₁ = 4P₂

or