Question

The excess pressure of one soap bubble is four times more than that in the other. Then the ratio of volumes of the first bubble to the second, is

• A. 1 : 64
• B. 1 : 4
• C. 64 : 1
• D. 1 : 2

Answer 1

Answer: (A)

1 : 64

Answer 2

or P₁ = 4P₂

$\frac { r _ { 1 } } { r _ { 2 } } = \frac { 1 } { 4 }$

$\frac { v _ { 1 } } { v _ { 2 } } = \frac { r _ { 1 } ^ { 3 } } { r _ { 2 } ^ { 3 } } = \left( \frac { 1 } { 4 } \right) ^ { 3 } = \frac { 1 } { 64 }$