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Question: The escape velocity of an object on a planet whose g value is 9 times on earth and whose radius is 4...

The escape velocity of an object on a planet whose g value is 9 times on earth and whose radius is 4 times that of earth in km/s is

A

67.2

B

33.6

C

16.8

D

25.2

Answer

67.2

Explanation

Solution

vpve=gpge×RpRe=9×4=6\frac { v _ { p } } { v _ { e } } = \sqrt { \frac { g _ { p } } { g _ { e } } \times \frac { R _ { p } } { R _ { e } } } = \sqrt { 9 \times 4 } = 6vp=6×ve=67.2 km/sv _ { p } = 6 \times v _ { e } = 67.2 \mathrm {~km} / \mathrm { s }