Solveeit Logo

Question

Physics Question on Gravitation

The escape velocity for the earth is 11.2km/sec11.2 \,km / sec. The mass of another planet 100100 times mass of earth and its radius is 44 times radius of the earth. The escape velocity for the planet is:

A

56.0 km/sec

B

280 km/sec

C

112 km/sec

D

56 km/sec

Answer

56.0 km/sec

Explanation

Solution

vescape =2GMRMRv_{\text {escape }}=\sqrt{\frac{2 G M}{R}} \propto \sqrt{\frac{M}{R}}, Hence, vpve=MpRp×ReMe\frac{v_{p}}{v_{e}}=\sqrt{\frac{M_{p}}{R_{p}} \times \frac{R_{e}}{M_{e}}} or vpve=100×14=5\frac{v_{p}}{v_{e}}=\sqrt{100 \times \frac{1}{4}}=5 vp=5×11.2=56km/secv_{p}=5 \times 11.2=56 \,km / sec