Question

The equivalent weight of phosphoric acid $(H_{3}PO_{4})$ in the reaction $NaOH + H_{3}PO_{4} \rightarrow NaH_{2}PO_{4} + H_{2}O$ is.

• A. 25
• B. 49
• C. 59
• D. 98

Answer 1

Answer: (D)

98

Answer 2

Molecular weight of $H_{3}PO_{4}$ is 98 and change in

its valency = 1 equivalent wt. of $H_{3}PO_{4}$

$= \frac{\text{Molecularweight}}{\text{Changeinvalency}} = \frac{98}{1} = 98$.