Chemistry Question on Importance and Applications of Coordination Compounds

Question

The equivalent weight of Mohrs salt is:

Answer 1

Solution

The molecular weight of Mohrs salt $(FeS{{O}_{4}}\cdot {{(N{{H}_{4}})}_{2}}S{{O}_{4}}\cdot 6{{H}_{2}}O)$ = 56+2 (32 + 64) + 2 (14 + 4) + 6 (18) = 56 +192 + 36 +108 = 392 $\therefore$ Equivalent weight of reductant $=\frac{\text{Mol}\text{.wt}\text{.}}{\text{increase}\,\text{in}\,\text{O}\text{.N}\text{.}}=\frac{392}{1}=392$ ( $\because$ $F{{e}^{2+}}$ changes into $F{{e}^{3+}}$ in its reactions)