Solveeit Logo
Login

Question

Chemistry Question on Some basic concepts of chemistry

The equivalent weight of MnSO4 {MnSO_4} is half its molecular weight when it is converted into

A

\ceMn2O3\ce{Mn_2O_3}

B

\ceMnO4−\ce{MnO^{-}_4}

C

\ceMnO2\ce{MnO_2}

D

\ceMnO42−\ce{MnO^{2-}_4}

Answer

\ceMnO2\ce{MnO_2}

Explanation

Solution

If a redox reaction involves two-electron change then the E wt. of the substance is half the molecular weight, i.e., {\overset{\text{+4}}{ {Mn }}O2−>O_2 ->\overset{\text{ +2}}{ {Mn }}SO_4}