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Question

Question: The equivalent resistance between A and B is: ...

The equivalent resistance between A and B is:

A

R1R_1

B

R2R_2

C

R2R4R2+R4+R1\frac{R_2 R_4}{R_2+R_4}+R_1

D

R1R4R1+R4\frac{R_1 R_4}{R_1 + R_4}

Answer

(D) R1R4R1+R4\frac{R_1 R_4}{R_1 + R_4}

Explanation

Solution

To find the equivalent resistance between points A and B, we need to analyze the circuit. Assume R3 is a short circuit (R3 = 0). Then the parallel combination of R2 and R3 becomes:

RDB=R2×0R2+0=0R_{DB} = \frac{R_2 \times 0}{R_2 + 0} = 0

This means the resistance between D and B is zero, effectively making D and B the same electrical point.

Now, the circuit simplifies:

  • R1 is connected between A and B.
  • R4 is connected between A and D. Since D is now effectively B, R4 is connected between A and B.

Therefore, R1 and R4 are in parallel. The equivalent resistance between A and B would be:

RAB=R1R4R1+R4R_{AB} = \frac{R_1 R_4}{R_1 + R_4}