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Question: The equivalent conductivity of N/10 solution of acetic acid at \(25ºC\) is \(14.3ohm^{- 1}cm^{2}equi...

The equivalent conductivity of N/10 solution of acetic acid at 25ºC25ºC is 14.3ohm−1cm2equiv−114.3ohm^{- 1}cm^{2}equiv^{- 1}. What will be the degree of dissociation of acetic acid?

(Δ∞CH3COOH=390.71ohm−1cm2equiv−1)(\Delta_{\infty CH_{3}COOH} = 390.71ohm^{- 1}cm^{2}equiv^{- 1})

A

3.66%3.66\%

B

3.9%3.9\%

C

2.12%2.12\%

D

0.008%0.008\%

Answer

3.66%3.66\%

Explanation

Solution

ΔmCH3COOH∞=390.71ohm−1cm2equiv−1\Delta_{mCH_{3}COOH}^{\infty} = 390.71ohm^{- 1}cm^{2}equiv^{- 1}

ΔCH3COOH=14.3ohm−1cm2equiv−1\Delta_{CH_{3}COOH} = 14.3ohm^{- 1}cm^{2}equiv^{- 1}

Degree of dissociation (α\alpha)

=ΔmcΔm∞=14.3390.71=0.0366i.e.3.66%= \frac{\Delta_{m}^{c}}{\Delta_{m}^{\infty}} = \frac{14.3}{390.71} = 0.0366i.e.3.66\%