Question
Question: The equivalent conductivity of N/10 solution of acetic acid at \({{25}^{0}}C\) is \(14.3oh{{m}^{-1}}...
The equivalent conductivity of N/10 solution of acetic acid at 250C is 14.3ohm−1cm2eq−1. Calculate the degree of dissociation of acetic acid if ∧∞CH3COOH is 390.71.
Solution
“The degree of dissociation is the fraction of original solute molecules that have dissociated”. Degree of dissociation is usually indicated by the symbol α. In detail, degree of dissociation refers to the amount of solute dissociated or ionized into ions or radicals per mole.
Complete Solution :
- Given that the equivalent conductivity of 0.1 N acetic acid solution at 250C is 14.3ohm−1cm2eq−1 .
- Given that the equivalent conductivity of acetic acid at infinite dilution is 390.71.
- Degree of dissociation is going to be denoted with the symbol α.
α=∧∞∧v
∧v = equivalent conductance acetic acid at dilution v = 14.3ohm−1cm2eq−1 .
∧∞= equivalent conductance of acetic acid at ∞ dilution of acetic acid = 390.71ohm−1cm2eq−1 .