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Question

Chemistry Question on Electrochemistry

The equivalent conductance of NaClNaCl at concentration CC and at infinite dilution are λC\lambda_C and λ\lambda_\infty respectively. The correct relationship between λC\lambda_C and λ\lambda_\infty is given as (where, the constant BB is positive)

A

λC=λ+(B)C\lambda_C = \lambda_\infty+(B)C

B

λC=λ(B)C\lambda_C = \lambda_\infty - (B)C

C

λC=λ(B)C\lambda_C = \lambda_\infty - (B)\sqrt C

D

λC=λ+(B)C\lambda_C = \lambda_\infty +(B)\sqrt C

Answer

λC=λ(B)C\lambda_C = \lambda_\infty - (B)\sqrt C

Explanation

Solution

According to Debye Huckle onsager equation,

λC=λAC\lambda_{C}=\lambda_{\infty}-A \sqrt{C}

Here A=BA = B
λC=λBC\therefore \, \lambda_{C}=\lambda_{\infty}-B \sqrt{C}