Question

The equivalent capacitance between the points A and B in the following circuit is:

• A.
• B. $2\mu F$
• C. $4\mu F$
• D. $8\mu F$

Answer 1

Answer: (A)

Answer 2

The two capacitors each of value $1.5\,\mu F$ are in parallel, so their equivalent capacitance. ${{C}_{1}}=1.5+1.5=3\,\mu F$ Now, three capacitors each of value $3\,\mu F$ are in series. Hence, their equivalent capacitance is given by $\frac{1}{C}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}$ or $\frac{1}{C}=\frac{3}{3}$ or $C=1\,\mu F$