Question

The equivalent capacitance between points A and B in below shown figure will be ______ μF.

Answer 1

The equivalent capacitance between points A and B is:
$C_{eq} = \frac {(3\times8)\times8}{(3\times8)+8}$

$C_{eq} = \frac {24\times 8}{24+8}$

$C_{eq} = \frac {24\times 8}{32}$

$C_{eq} = 6\ μF$

So, the answer is $6\ μF$.