Question
Physics Question on Combination of capacitors
The equivalent capacitance between A and B is,
A
150 pF
B
50 pF
C
300 pF
D
3100pF
Answer
3100pF
Explanation
Solution
CAB=(50∣∣50)series50=100+50100×50=3100pF
The equivalent capacitance between A and B is,
150 pF
50 pF
300 pF
3100pF
3100pF
CAB=(50∣∣50)series50=100+50100×50=3100pF