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Question

Physics Question on Combination of capacitors

The equivalent capacitance between A and B is,

A

150 pF

B

50 pF

C

300 pF

D

1003pF\quad\frac{100}{3} pF

Answer

1003pF\quad\frac{100}{3} pF

Explanation

Solution

CAB=(5050)series50=100×50100+50=1003pF\quad C_{AB}=\left(50 ||50\right) series \,50=\frac{100\times50}{100+50}=\frac{100}{3} pF