Question

The equilibrium constants of the following are.
$N_2+3H_2⇋NH_3$ $K_1$
$N_2+O_2⇋2No$ $K_2$
$H_2+\frac 12O_2⇋H_2O$ $K_3$
The equilibrium constant $(K)$ of the reaction:
$2NH_3+\frac 52O_2⇋2NO+3H_2O$
will be

• A. $\frac {K_1K_3^3}{K_2}$
• B. $\frac {K_2K_3^3}{K_1}$
• C. $\frac {K_2K_3}{K_1}$
• D. $\frac {K_2^3K_3}{K_1}$

Answer 1

Answer: (B)

$\frac {K_2K_3^3}{K_1}$

Answer 2

The correct option is (B): $\frac {K_2K_3^3}{K_1}$.