Question

The equilibrium constants andfor the reactions X 2Y and Z P + Q, respectively are in the ratio of 1 : 9. If the degree of dissociation of X and Z be equal then the ratio of total pressures at these equilibria is

• A. 1 : 1
• B. 1 : 3
• C. 1 : 9
• D. 1 : 36

Answer 1

Answer: (D)

1 : 36

Answer 2

X 2Y Z P + Q

$1 - \alpha$ $2 \alpha$ $1 - \alpha$ $\alpha$ $\alpha$

$\mathrm { K } _ { \mathrm { p } _ { 2 } } = \frac { \left( \frac { \alpha } { 1 + \alpha } \mathrm { P } _ { \mathrm { T } _ { 2 } } \right) \left( \frac { \alpha } { 1 + \alpha } \mathrm { P } _ { \mathrm { T } _ { 1 } } \right) } { \left( \frac { 1 - \alpha } { 1 + \alpha } \mathrm { P } _ { \mathrm { T } _ { 2 } } \right) }$

$\frac { 1 } { 9 } = \frac { 4 \mathrm { P } _ { \mathrm { T } _ { 1 } } } { \mathrm { P } _ { \mathrm { T } _ { 2 } } } ; \quad \frac { \mathrm { P } _ { \mathrm { T } _ { 1 } } } { \mathrm { P } _ { \mathrm { T } _ { 2 } } } = \frac { 1 } { 36 }$