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Question: The equilibrium constant (K<sub>c</sub>) for the reaction <img src="https://cdn.pureessence.tech/can...

The equilibrium constant (Kc) for the reaction ⇌BH++A−\mathrm { BH } ^ { + } + \mathrm { A } ^ { - } is 100. If the rate constant for the forward reaction is 105, then rate constant for the backward reaction is.

A

10710 ^ { 7 }

B

10310 ^ { 3 }

C

10−310 ^ { - 3 }

D

10−510 ^ { - 5 }

Answer

10310 ^ { 3 }

Explanation

Solution

Kc=KfKb∴Kb=KfKc=105100=103\mathrm { K } _ { \mathrm { c } } = \frac { \mathrm { K } _ { \mathrm { f } } } { \mathrm { K } _ { \mathrm { b } } } \therefore \mathrm { K } _ { \mathrm { b } } = \frac { \mathrm { K } _ { \mathrm { f } } } { \mathrm { K } _ { \mathrm { c } } } = \frac { 10 ^ { 5 } } { 100 } = 10 ^ { 3 }