Solveeit Logo

Question

Question: The equilibrium constant. K<sub>c</sub> for the reaction P<sub>4</sub>(g) ![](https://cdn.pureessen...

The equilibrium constant. Kc for the reaction

P4(g) 2P2(g)

is 1.4 at 400°C. Suppose that 3 moles of P4(g) and 2 moles of P2(g) are mixed in 2 litre container at 400°C. What is the value of reaction quotient (Q)-

A

3/2

B

2/3

C

1

D

None of these

Answer

2/3

Explanation

Solution

Qc = [P2( g)]4[P4( g)]\frac { \left[ \mathrm { P } _ { 2 } ( \mathrm {~g} ) \right] ^ { 4 } } { \left[ \mathrm { P } _ { 4 } ( \mathrm {~g} ) \right] }= (1)2(3/2)\frac { ( 1 ) ^ { 2 } } { ( 3 / 2 ) }= 2/3