Question

The equilibrium constant for the reaction
$Zn(s)+Sn^{2+}(aq)⇌Zn^{2+}(aq)+Sn(s)\, is\, 1×10^{20}$ at $298 K$.
The magnitude of standard electrode potential of $Sn/Sn^{2+}$ if $E^{\degree}_{ Zn^{2+}/Zn}= –0.76V$ is _______ $×10^{−2} V$. (Nearest integer).
(Given : $\frac{2.303RT}{ F}$ $=0.059 V$)

Answer 1

The answer is 17.