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Chemistry Question on Law Of Chemical Equilibrium And Equilibrium Constant

The equilibrium constant for the reaction N2+3H2⇌2NH3N_{2} +3H_{2} {\rightleftharpoons} 2NH_{3} is ?K?. Then, the equilibrium constant for the reaction 2N2+6H2⇌4NH32N_{2}+6H_{2} {\rightleftharpoons} 4NH_{3} will be

A

K

B

K2K^{2}

C

K\sqrt{K}

D

2K

Answer

K2K^{2}

Explanation

Solution

For the reaction
N2+3H2⇌ 2NH3,N_{2}+3H_{2} {\rightleftharpoons} \,2NH_{3}, equilibrium constant = K. ∴K=[NH3]2[N2][H2]3\therefore K=\frac{\left[NH_{3}\right]^{2}}{\left[N_{2}\right]\left[H_{2}\right]^{3}} Now, for 2N2+6H2⇌ 4NH3, K′=[NH3]4[N2]2[H2]6=K22N_{2}+6H_{2} {\rightleftharpoons}\,4NH_{3},\, K^{'}=\frac{\left[NH_{3}\right]^{4}}{\left[N_{2}\right]^{2}\left[H_{2}\right]^{6}}=K^{2}