Question

The equilibrium constant for a reaction is 10. What will be the value of $\Delta G^{o}$ at 300 K?

• A. $- 5.74kJ$
• B. – 574 Kj
• C. $+ 11.48kJ$
• D. $+ 5.74kJ$

Answer 1

Answer: (A)

$- 5.74kJ$

Answer 2

: $\Delta G = - 2.303RT\log K$

$= 2.303 \times 8.314 \times 300\log 10 = - 5744.1Jor - 5.74kJ$