Question

The equilibrium concentration of $X , Y$ and $Y X _ { 2 }$ are 4, 2 and 2 moles respectively for the equilibrium $2 X + Y$⇌$Y X _ { 2 }$. The value of $K _ { c }$ is.

• A. 0.625
• B. 0.0625
• C. 6.25
• D. 0.00625

Answer 1

Answer: (B)

0.0625

Answer 2

$\mathrm { K } _ { \mathrm { c } } = \frac { \left[ \mathrm { YX } _ { 2 } \right] } { [ \mathrm { X } ] ^ { 2 } [ \mathrm { Y } ] } = \frac { 2 } { 4 \times 4 \times 2 } = \frac { 1 } { 16 } = 0.0625$.