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Question: The equatorial magnetic field of earth is 0.4 G. Then its dipole moment on equator is...

The equatorial magnetic field of earth is 0.4 G. Then its dipole moment on equator is

A

1.05 x 1023 A m2

B

2.05 x 1023 Am2

C

1.05 x 1021 Am2

D

2.05 x l021Am2

Answer

1.05 x 1023 A m2

Explanation

Solution

: Here, , bE=0.4G=0.4×104 T\mathrm { b } _ { \mathrm { E } } = 0.4 \mathrm { G } = 0.4 \times 10 ^ { - 4 } \mathrm {~T}

As (pwˇfd), BE=μ04πr3B _ { E } = \frac { \mu _ { 0 } } { 4 \pi r ^ { 3 } }

\therefore

=0.4×104×(6.4×106)3107= \frac { 0.4 \times 10 ^ { - 4 } \times \left( 6.4 \times 10 ^ { 6 } \right) ^ { 3 } } { 10 ^ { - 7 } }